z^2+z-1-3i=0

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Solution for z^2+z-1-3i=0 equation:


Simplifying
z2 + z + -1 + -3i = 0

Reorder the terms:
-1 + -3i + z + z2 = 0

Solving
-1 + -3i + z + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + -3i + z + 1 + z2 = 0 + 1

Reorder the terms:
-1 + 1 + -3i + z + z2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -3i + z + z2 = 0 + 1
-3i + z + z2 = 0 + 1

Combine like terms: 0 + 1 = 1
-3i + z + z2 = 1

Add '-1z' to each side of the equation.
-3i + z + -1z + z2 = 1 + -1z

Combine like terms: z + -1z = 0
-3i + 0 + z2 = 1 + -1z
-3i + z2 = 1 + -1z

Add '-1z2' to each side of the equation.
-3i + z2 + -1z2 = 1 + -1z + -1z2

Combine like terms: z2 + -1z2 = 0
-3i + 0 = 1 + -1z + -1z2
-3i = 1 + -1z + -1z2

Divide each side by '-3'.
i = -0.3333333333 + 0.3333333333z + 0.3333333333z2

Simplifying
i = -0.3333333333 + 0.3333333333z + 0.3333333333z2

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